How do you simplify #(3x-8)/(6x^2-16x)# and then find the excluded values?
1 Answer
Jul 21, 2017
Explanation:
#"simplify thedenominator by factorising"#
#(3x-8)/(2x(3x-8))larrcolor(blue)" common factor of 2x"#
#"cancel the common factor " (3x-8)#
#(cancel((3x-8)))/(2xcancel((3x-8)))=1/(2x)#
#rArr(3x-8)/(6x^2-16x)#
#=1/(2x)tox!=0larrcolor(red)" excluded value"#
