# How do you simplify (3xy^4)/(2x^5y) *( 6x^-3y^2)/(4y)?

Jul 8, 2016

$\frac{9 {y}^{4}}{4 {x}^{7}}$

#### Explanation:

remember:

${a}^{b} \cdot {a}^{c} = {a}^{b + c}$

work

$\frac{3 x {y}^{4}}{2 {x}^{5} y} \cdot \frac{6 {x}^{-} 3 {y}^{2}}{4 y}$

Simplify by dividing out factors in the top and bottom

$\frac{3 {y}^{3}}{2 {x}^{4}} \cdot \frac{3 {x}^{-} 3 y}{2}$

Now change the ${x}^{-} 3$ into $\frac{1}{x} ^ 3$ and bring it into the denominator since anything to a negative power is one over that number to the positive exponent

$\frac{3 {y}^{3}}{2 {x}^{4}} \cdot \frac{3 y}{2 {x}^{3}}$

Now we can multiply

$\frac{3 {y}^{3} \times 3 y}{2 {x}^{4} \times 2 {x}^{3}}$

And simplify

$\frac{9 {y}^{4}}{4 {x}^{7}}$