# How do you simplify (3y^2)(2y^3)?

$6 {y}^{5}$

#### Explanation:

Given that

$\left(3 {y}^{2}\right) \left(2 {y}^{3}\right)$

$= \left(3 \setminus \cdot 2\right) \left({y}^{2} \setminus \cdot {y}^{3}\right)$

$= \left(6\right) \left({y}^{2 + 3}\right)$

$= 6 {y}^{5}$

Jul 22, 2018

$6 {y}^{5}$

#### Explanation:

Since we are multiplying, we can group the like terms to get

$\textcolor{s t e e l b l u e}{3 \cdot 2} \cdot \textcolor{p u r p \le}{{y}^{2} \cdot {y}^{3}}$

Notice, this expression is saying the same thing as the one in the question, but it can sometimes help to group like terms.

Recall that when we multiply exponents with the same base, we add the powers. This simplifies to

$\textcolor{s t e e l b l u e}{6} \textcolor{p u r p \le}{{y}^{5}}$

Hope this helps!