How do you simplify #((3y^3)(2y^2)^-2)/(y^4)^3# and write it using only positive exponents?

1 Answer
Apr 7, 2017

Answer:

#3/(4y^13#

Explanation:

You can get rid of the negative index by using one of the laws of indices: #x^-m = 1/x^m#
The whole bracket moves to the denominator and the index becomes positive.

#((3y^3)color(red)((2y^2)^-2))/(y^4)^3 = (3y^3)/(color(red)((2y^2)^2)(y^4)^3)#

Now use the power law of indices #(x^m)^n = x^mn#

#(3y^3)/((4y^4 y^12)#

Simplifying gives:

#3/(4y^13#