How do you simplify (3y^3)^3(4y^2)^-3 and write it using only positive exponents?

Jul 24, 2017

See below.

Explanation:

Let's take each expression separately.

${\left(3 {y}^{3}\right)}^{3} = 27 {y}^{9}$

${\left(4 {y}^{2}\right)}^{-} 3 = \frac{1}{64} {y}^{-} 6 = \frac{1}{64 {y}^{6}}$

Multiplying,

$27 {y}^{9} \setminus \cdot \frac{1}{64 {y}^{6}} = \frac{27}{64} \setminus \cdot {y}^{9} / {y}^{6} = \frac{27}{64} {y}^{3}$