How do you simplify #4 1/4 div 2#?

2 Answers
Sep 22, 2016

#4 1/4-:2=2 1/8#

Explanation:

While using fractions, we convert division into multiplication by taking the multiplicative inverse or reciprocal of the divisor.

As reciprocal of a fraction is nothing but numerator and denominator reversed, if we have to divide #a/b# by #c/d#, we just multiply #a/b# and #d/c#.

If one of the numbers is not a fraction, we write it as fraction. For example #p# as #p/1#.

Hence #4 1/4-:2#

= #(4xx4+1)/4-:2/#

= #17/4xx1/2=(17xx1)/(4xx2)=17/8#

= #(2xx8+1)/8=(2xx8)/8+1/8=2 1/8#

Oct 3, 2016

#17/8#

Full explanation given as to how it all works.

Explanation:

Given:#" "4 1/4 -:2#

,~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Consider the #4 1/4#

Write as:#" "4+1/4#

Multiply by 1 and you do not change the value, but 1 comes in many forms. So we can change the way it looks without changing the intrinsic value.

Multiply the 4 by 1 but in the form of #color(magenta)(1=4/4)#

#[4color(magenta)(xx4/4)]+1/4#

#[16/4]+1/4" "=" "(16+1)/4#

#"So "4 1/4" is the same as "17/4#
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Putting it all together: #-> 17/4-:2#

#color(magenta)("Shortcut method "->" Invert the 2 and multiply")#

#color(blue)(17/4xx1/2 = 17/8) larr" shortcuts make calculation faster"#

'.............................................................................................
#color(magenta)("First principle method "->" turn the 2 into quarters")#

Multiply the 2 by 1 but in the form of #color(green)(1=4/4)#

#17/4-:[2color(green)(xx4/4)]#

#17/4-:8/4#

Fraction structure is #("count")/("size indicator")" "->" "("numerator")/("denominator")#

#color(brown)("As both the size indicators are the same we can just divide counts")#

#=> 17/4-:8/4" "=" "17-:8" "=" "color(blue)(17/8)#