How do you simplify #(4^-1 * 7) ^ 2#?

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Answer 1 · 2018-07-06T17:26:37

#49/16#

#"using the "color(blue)"law of exponents"#

#•color(white)(x)a^-mhArr1/a^m#

#(4^-1xx7)^2#

#=(1/4xx7)^2#

#=(7/4)^2=7/4xx7/4=(7xx7)/(4xx4)=49/16#

Answer 2 · 2018-07-06T17:41:09

#49/16#

When we distribute an exponent to another exponent, we multiply the powers. Doing this, we now have

#4^(-2)*7^2#

When we have a negative exponent, we can make it positive by taking it to the denominator. We now have

#1/(4^2)*7^2=(7^2)/(4^2)=49/16#

Hope this helps!