How do you simplify #(4 / 2) + 4(5 - 2)^2 # using PEMDAS?

2 Answers
Mar 27, 2018

Answer:

#38#

Explanation:

#"simplify using PEMDAS"#

#["P-parenthesis (brackets), E-exponents (powers), "#
#"M-multiplication, D-division, A-addition, S-subtraction"]#

#rArr2+4(3)^2larrcolor(red)"parenthesis"#

#=2+4xx9larrcolor(red)"exponents"#

#=2+36larrcolor(red)"multiplication"#

#=38larrcolor(red)"addition"#

Mar 27, 2018

Answer:

#38#

Explanation:

The most important thing is to identify and count the number of TERMS first.

Terms are separated by #+ and -# signs.

Each term is simplified to a single answer and they are added or subtracted in the last step.

Within each term: the order is

Brackets
powers and roots
Of
multiplication and division

#" "color(blue)((4 / 2))color(red)( + 4(5 - 2)^2)" "larr# there are 2 terms
#" "darr color(white)(xxx..x)darr" "# division and subtraction
#=color(blue)((2))" "color(red)( +" " 4(3)^2)#
#" "darr color(white)(xxx..x)darr#
#=color(blue)(2)" "color(red)( +" " 4(9)#
#" "darr color(white)(xxxx.x)darr#
#=color(blue)(2)" "color(red)( +" " 36)#

#=38#