How do you simplify #(4-2(x-1))/(x^2-6x+9)#?

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Answer 1 · 2015-11-26T14:49:09

#(-2)/(x-3)#

#(4-2(x-1))/(x^2-6x+9)#

#=(4-2x+2)/(x^2-6x+9)#

#=(-2x+6)/(x^2-6x+9#

#=(-2(x-3))/((x-3)(x-3))#

#=(-2color(red)cancelcolor(black)((x-3)))/(color(red)cancelcolor(black)((x-3))(x-3))#

#=(-2)/(x-3)#

Note:
#(4-2(x-1))/(x^2-6x+9)# is not the same as #((4-2)(x-1))/(x^2-6x+9)#