How do you simplify $4 + 3 (- 6) - 1$ $4 + 3(-6) - 1$ using order of operations?

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Answer 1 · 2018-07-09T23:06:26

$- 15$ $-15$

$4 + 3 (- 6) - 1$ $4 + 3(-6) - 1$

PEMDAS (the order of operations) is shown here:
www.coolmath.com

The first thing to do is multiplication:
$4 - 18 - 1$ $4 - 18 - 1$

Subtract from left to right:
$- 14 - 1$ $-14 - 1$

$= - 15$ $=-15$

Hope this helps!

Answer 2 · 2018-07-09T23:39:15

$- 15$ $-15$

Multiplication takes precedence over addition/subtraction, so we can do $3 \cdot - 6$ $3*-6$ first to get $- 18$ $-18$ . We now have

$4 - 18 - 1$ $4-18-1$

We can work from left to right to get

$- 14 - 1 = - 15$ $-14-1=-15$

Hope this helps!

How do you simplify 4+3(−6)−14 + 3(-6) - 1 using order of operations?