# How do you simplify (4^-4)^-2 and write it using only positive exponents?

Sep 30, 2016

${4}^{8}$

#### Explanation:

Recall one of the laws of indices..

${\left({x}^{m}\right)}^{n} = {x}^{m n} \text{ } \leftarrow$ a power to a power, multiply the indices

${\left({4}^{-} 4\right)}^{-} 2 = {4}^{- 4 \times - 2}$

$= {4}^{8}$

As this is a really big number, this is a better form of the answer.