How do you simplify #(4*(-9))/-6#? Algebra Expressions, Equations, and Functions PEMDAS 1 Answer Özgür Özer Dec 11, 2015 #6# Explanation: #color(white)(xxx)(4*(-9))/-6=(4*(-9)color(red)(*-1/2*1/3))/(-6color(red)(*-1/2*1/3))# #color(white)(xxxxxxxxx)=(color(red)(2*3))/color(red)1# #color(white)(xxxxxxxxx)=6# Answer link Related questions What is PEMDAS? How do you use PEMDAS? How do you use order of operations to simplify #3(7-2)-8#? What are common mistakes students make with PEMDAS? How do you evaluate the expression #5[8+(3-1)]-2#? How do you simplify the expression #4(30-(3+1)^2)#? How do you evaluate the expression #x^4+x# if x=2? Is it okay to add first before subtracting in #4-6+3#? How do you simplify #(-3)^2+12*5#? How do you simplify #(4-2)^3-4*8+21div3#? See all questions in PEMDAS Impact of this question 1410 views around the world You can reuse this answer Creative Commons License