How do you simplify #4/(d-1)+d/(1-d)#?

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Answer 1 · 2016-12-22T19:00:31

#(d-4)/(1-d)#

#4/(d-1)+d/(1-d)#

#(-4)/(1-d)+d/(1-d)" "# make the denominators the same

#(-4+d)/(1-d)#

#(d-4)/(1-d)#

Answer 2 · 2016-12-22T19:18:50

#(d-4)/(1-d)#

#4/(d-1)+d/(1-d)#

#(4(1-d)+d(d-1))/((d-1)(1-d))#

#((4-4d+d^2-d))/((d-1)(1-d))#

#((d^2-5d+4))/((d-1)(1-d))#

#((d-4)(d-1))/((d-1)(1-d))#

#(d-4)/(1-d)#