How do you simplify #(4+sqrt50)-(3-sqrt(8)) #?

Question

1811 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-03-31T13:33:00

#=1+7sqrt2#

#sqrt50=5sqrt2# and #sqrt8=2sqrt2#

Equation becomes #(4+5sqrt2)-(3-2sqrt2)#

#=4+5sqrt2-3+2sqrt2#

#=1+7sqrt2#

Answer 2 · 2018-03-31T13:33:45

#(4+sqrt50)-(3-sqrt8)=1+7sqrt2#

#(4+sqrt50)-(3-sqrt8)#

#sqrt50=sqrt(25xx2)=sqrt25xxsqrt2=5sqrt2#

#sqrt8=sqrt(4xx2)=sqrt4xxsqrt2=2sqrt2#

#(4+sqrt50)-(3-sqrt8)=(4+5sqrt2)-(3-2sqrt2)#

#=4+5sqrt2-3+2sqrt2#

#=(4-3)+(5sqrt2+2sqrt2)#

#=1+7sqrt2#

#(4+sqrt50)-(3-sqrt8)=1+7sqrt2#