How do you simplify #[4 times (5+6)] ÷ (4² - 12)^3# using PEMDAS?

1 Answer

Answer:

Answer#=11/16#

Explanation:

#[4*(5+6)] div (4^2-12)^3#

Work on the inside of PARENTHESIS first ....that means the innermost PARENTHESIS. So we start with 5+6 then multiply by 4, and on the other one #4^2# first before subtracting 12

#[4*11] div (16-12)^3#

At this point EXPONENTIAL first before DIVISION
#44 div 4^3#

#44 div 64#

#44/64#

#11/16#

God bless...I hope the explanation is useful..