How do you simplify (42y^7)/(9y^8x)?

Apr 10, 2015

The answer is $\frac{14}{3 y x}$

Simplify $\frac{42 {y}^{7}}{{y}^{8} x}$

Simplify the coefficients.

$\frac{42}{3} = \frac{\left(\cancel{3}\right) \cdot 2 \cdot 7}{\left(\cancel{3}\right) \cdot 3} = \frac{14}{3}$

Simplify the variables.

$\frac{{y}^{7}}{{y}^{8} x} = \frac{{y}^{7 - 8}}{x} = {y}^{- 1} / \left(x\right) = \frac{1}{y x}$

Multiply the simplified coefficients and variables.

$\frac{14}{3} \cdot \frac{1}{y x} = \frac{14}{3 y x}$