How do you simplify #47-14 3/7-11 2/21#?

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Answer 1 · 2018-04-25T07:12:35

#21 10/21#

Deal with the whole numbers first

#47-14=33#
#33-11=22#

so we now have #22-3/7-2/21#

#3/7=6/14=9/21# so if I substitute #9/21# for #3/7# in the question I get

#22-9/21-2/21#
Put the two fractions together to do one subtraction

#-9/21-2/21=-11/21#

#=>##22-11/21#
If I take one whole number and change it into a fraction with 21 as the denominator I would get #21/21#. Now I can do the subtraction

#21 21/21-11/21#

#21 10/21#

Answer 2 · 2018-04-25T07:15:16

The answer is #21 10/21#.

#47-(14+3/7)-(11+2/21)#

#=47-14-11-(3/7+2/21)#

#=47-25-(11/21)#

#=22-11/21#

#=(462-11)/21#

#=451/21#

#=21+10/21#

#=21 10/21#