How do you simplify #49\div 7+ 10[ 3( 9- 2) - 2( 17- 8) ]#?

2 Answers
Apr 28, 2018

Answer:

The answer is #37#.

Explanation:

Work the problem with PEMDAS

#49/7+10[3(9-2)-2(17-8)]#

Take care of the inner parenthesis first:

#49 div 7+10[3*7-2*9]#

Now deal with the brackets:

#49 div 7+10[21-18] #

#49 div 7+10*3 #

Left to right, do the multiplication and division:

#7+30 #

Now do the last addition:

#37#

Apr 29, 2018

Answer:

#37#

Explanation:

When doing calculations with multiple operations:

Identify the different terms first. (Separated by #+ and -# signs)

Within each term, use the order:

  • brackets
  • powers and roots
  • multiply and divide (in any order)

Then re-arrange the terms so the additions are at the front.

  • then add and do the subtractions last.

#color(blue)(49\div 7) " "color(red)(+" " 10[ 3( 9- 2) - 2( 17- 8) ])" "larr# inner brackets
#color(white)(xx)darrcolor(white)(xxxxxxxxxx)darrcolor(white)(xxxxxxx)darr#
#=color(blue)(7)color(white)(xxxx)color(red)(+color(white)(x.x) 10[ 3( 7)color(white)(xx) -color(white)(xx) 2(9) ])" "larr# multiply brackets
#color(white)(xx)darrcolor(white)(xxxxxxxxxx)darrcolor(white)(xxxxxxx)darr#
#=color(blue)(7)color(white)(xxxx)color(red)(+color(white)(x..x) 10[21color(white)(x.x) -color(white)(x.x) 18 ])" "larr# subtract
#color(white)(xx)darrcolor(white)(xxxxxxxxxxxxxx)darr#
#=color(blue)(7)color(white)(xxxx)color(red)(+color(white)(x....xxxxx) 10[3 ])" "larr# multiply the bracket
#color(white)(xx)darrcolor(white)(xxxxxxxxx.xxxx)darr#
#=color(blue)(7)color(white)(xxxx)color(red)(+color(white)(x....xxxxxx) 30)" "larr# add the two terms

#=37#