# How do you simplify ((4a^3b)/(a^2b^3))*((3b^2)/(2a^2b^4))?

$\frac{6}{a {b}^{4}}$
Exponents with the same base would add on multiplication = $\frac{12}{2}$ $\frac{{a}^{3} {b}^{3}}{{a}^{4} {b}^{7}}$
= $\frac{6}{a {b}^{4}}$ [exponents in the numerator being lesser than those in the denominator, on division these would subtract from the greater exponents. This would result in the simplification being with positive exponents.]