# How do you simplify (4fg^-5)/(5h^-3) using only positive exponents?

The answer would be $\frac{4 f {h}^{3}}{5 {g}^{5}}$
$\frac{4 f {g}^{-} 5}{5 {h}^{-} 3}$
$\frac{4 f {h}^{3}}{5 {g}^{5}}$
When you have a negative exponent, it just means the number being raised to a power is on the wrong side of the fraction line - If it is in the numerator it should be in the denominator, and vice versa. For example, if I have ${9}^{-} 1$, it is equivalent to $\frac{{9}^{-} 1}{1}$. To simplify it i would just move the $9$ to the denominator, and it would be $\frac{1}{9}$.