How do you simplify $4i(-2-8i)$ ?

Question

5289 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-04-15T02:25:31

The answer is $-8i+32$ .

Simplifying $4i(-2-8i)$ :

First, factor out the $4i$ : $-8i-32i^2$ .

Because $i$ , an imaginary number, is equal to $sqrt(-1)$ , $i^2$ (or $(sqrt(-1))^2$ should be $-1$ .

Therefore, you can substitute in $-1$ for $i^2$ . Therefore your answer is $-8i-(32*-1)$ . This simplifies to your final answer, $-8i+32$ .

Hope this helps!

How do you simplify 4i(-2-8i)4i(-2-8i)?