How do you simplify 4n^4*2n^-3 and write it using only positive exponents?

Mar 4, 2018

$8 {n}^{1} = 8 n$

Explanation:

We have:

$4 {n}^{4} \cdot 2 {n}^{-} 3$

$= 4 \cdot {n}^{4} \cdot 2 \cdot {n}^{-} 3$

$= 8 {n}^{4} {n}^{-} 3$

Using exponent rules, ${a}^{b} \cdot {a}^{c} = {a}^{b + c}$.

So, we get

$= 8 {n}^{4 - 3}$

$= 8 {n}^{1}$

$= 8 n$

That's all!