How do you simplify #4n^-4# and write it using only positive exponents?

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Answer 1 · 2017-12-22T00:26:07

#4/n^4#

We use the property that #a^(-b)=1/a^b#, so:

#4n^-4=4*(1/n^4)=4/n^4#

Answer 2 · 2017-12-22T00:28:35

#4n^(-4)=color(blue)(4/(n^4))#

Remember that in general
#color(white)("XXX")a^(-b)=1/(a^b)#

#n^(-4)=4 * n^(-4)#

#color(white)("XX")=4 * 1/(n^4)#

#color(white)("XX")=4/(n^4)#