# How do you simplify 4sqrt13-sqrt13?

Jul 1, 2016

$3 \sqrt{13}$
1) we recognize that $4 \sqrt{13}$ = $\sqrt{13} + \sqrt{13} + \sqrt{13} + \sqrt{13}$ So when you substitute that into the equation you get:
$\sqrt{13} + \sqrt{13} + \sqrt{13} + \sqrt{13} - \sqrt{13} = \sqrt{13} + \sqrt{13} + \sqrt{13} = 3 \sqrt{13}$
2) we factor $\sqrt{13}$ out,leaving us with $\left(4 - 1\right) \cdot \sqrt{13} = 3 \sqrt{13}$