# How do you simplify ((4x^-2)/(5y^-3))^-3?

$= \frac{125}{64} \times {x}^{6} / {y}^{9}$
${\left(\frac{4 {x}^{-} 2}{5 {y}^{-} 3}\right)}^{-} 3 = \frac{{4}^{-} 3 \cdot {x}^{\left(- 2\right) \cdot \left(- 3\right)}}{{5}^{-} 3 \cdot {y}^{\left(- 3\right) \cdot \left(- 3\right)}} = {5}^{3} / {4}^{3} \times {x}^{6} / {y}^{9} = \frac{125}{64} \times {x}^{6} / {y}^{9}$