How do you simplify #(4x^2+y)/(x+y) + (x^2-y^2)/(x+y)#?

Question

1340 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-04-10T03:00:38

#(4x^2+y)/(x+y)+x-y#

Simplify:

#(4x^2+y)/(x+y)+(x^2-y^2)/(x+y)#

Use difference of squares:

#(a^2-b^2)=(a+b)(a-b)#,

where: #a=x# and #b=y#.

#(4x^2+y)/(x+y)+(color(red)cancel(color(black)((x+y)))^1(x-y))/color(red)cancel(color(black)((x+y)))^1#

#(4x^2+y)/(x+y)+x-y#