How do you simplify #( 4x ^-5y^2)^-3#?

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Answer 1 · 2016-07-05T16:06:59

#x^15/(64y^6)#

To simplify #(4x^-5y^2)^-3#

Begin by distributing the external exponent into the parenthesis

#4^-3x^(-5(-3))y^(2(-3))#

#4^-3x^15y^-6#

Eliminate the negative exponents in the numerator by moving those units to the denominator

#x^15/(4^3y^6)#

Simplify the cube of #4#

#x^15/(64y^6)#