How do you simplify #( 4x ^-5y^2)^-3#?

1 Answer
Jul 5, 2016

Answer:

#x^15/(64y^6)#

Explanation:

To simplify #(4x^-5y^2)^-3#

Begin by distributing the external exponent into the parenthesis

#4^-3x^(-5(-3))y^(2(-3))#

#4^-3x^15y^-6#

Eliminate the negative exponents in the numerator by moving those units to the denominator

#x^15/(4^3y^6)#

Simplify the cube of #4#

#x^15/(64y^6)#