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How do you simplify #(4xy^2)^4(2y)^-3#?

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NJ Share
Jun 19, 2018

Answer:

#=32x^4y^5#

Explanation:

#(4xy^2)^4(2y)^(-3)#

#=(4^4x^4y^((2xx4)))(2^(-3)y^(-3))#

#=(256x^4y^8)(1/8y^(-3))#

#=32x^4y^((8-3))#

#=32x^4y^5#

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