How do you simplify #(4y)^7/(4y)^3#? Algebra Exponents and Exponential Functions Exponential Properties Involving Quotients 1 Answer Don't Memorise Apr 13, 2015 In general #color(blue)(a^m/a^n = a^(m-n)# Here #a# is #4y# #(4y)^7/(4y)^3# # = (4y)^(7-3) # # = (4y)^4 # # = 4^4 * y^4# (In general, #color(blue)((ab)^m = a^m * b^m#) #color(green)( = 256y^4# Answer link Related questions What is the quotient of powers property? How do you simplify expressions using the quotient rule? What is the power of a quotient property? How do you evaluate the expression #(2^2/3^3)^3#? How do you simplify the expression #\frac{a^5b^4}{a^3b^2}#? How do you simplify #((a^3b^4)/(a^2b))^3# using the exponential properties? How do you simplify #\frac{(3ab)^2(4a^3b^4)^3}{(6a^2b)^4}#? Which exponential property do you use first to simplify #\frac{(2a^2bc^2)(6abc^3)}{4ab^2c}#? How do you simplify #(x^5y^8)/(x^4y^2)#? How do you simplify #[(2^3 *-3^2) / (2^4 * 3^-2)]^2#? See all questions in Exponential Properties Involving Quotients Impact of this question 1513 views around the world You can reuse this answer Creative Commons License