How do you simplify #5(2^3+4)/sqrt 36 times 7# using PEMDAS?
First, there are no explicitly written parentheses, but the numerator of the fraction must be computed first for the problem to make sense. This term is calculated by first computing
#5 xx 12/sqrt(36) xx7#
Next compute any terms with exponents. There is one exponent left which is hidden in the denominator. Note that
#5 xx 12/6 xx7#
Finally, perform all of the multiplication and division by moving left to right.
#5 xx 12/6 xx 7=60/6 xx 7=10 xx 7=70#