How do you simplify #5/5 div 1/2#?

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Answer 1 · 2018-03-10T10:20:59

See explanation.

To simplify such expressions you can change them to multiplication using:

#a/b -:c/d=a/bxxd/c#

Here you get:

#5/5-:1/2=5/5xx2/1=10/5=2#

Note: You could also start by reducing the first fraction:

#5/5 -: 1/2=1/1 -:1/2=1/1xx2/1=2/1=2#