How do you simplify $\frac{5}{6 x^{3} + x} \div (x^{2} - 12 x)$ $5/(6x^3 + x)div(x^2-12x)$ ?

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Answer 1 · 2018-03-22T14:41:17

$= \frac{5}{x^{2} (6 x^{2} + 1) (x - 12)}$ $=5/(x^2(6x^2+1)(x-12))$

$\frac{5}{6 x^{3} + x} \div (x^{2} - 12 x)$ $5/(6x^3+x) ÷ (x^2 -12x )$

$= \frac{5}{6 x^{3} + x} \cdot \frac{1}{x^{2} - 12 x}$ $= 5/(6x^3+x) * 1/(x^2 -12x )$

$= \frac{5}{6 x^{5} - 72 x^{4} + x^{3} - 12 x^{2}}$ $= 5/ (6x^5-72x^4+x^3-12x^2)$

$= \frac{5}{x^{2} (6 x^{3} - 72 x^{2} + x - 12)}$ $=5/(x^2(6x^3-72x^2+x-12)$

$= \frac{5}{x^{2} (6 x^{2} (x - 12) + 1 (x - 12))}$ $=5/(x^2(6x^2(x-12)+1(x-12)))$

$= \frac{5}{x^{2} (6 x^{2} + 1) (x - 12)}$ $=5/(x^2(6x^2+1)(x-12))$

How do you simplify 56x3+x÷(x2−12x)5/(6x^3 + x)div(x^2-12x)?