# How do you simplify 5a^-1 and write it using only positive exponents?

Oct 11, 2017

See explanation

#### Explanation:

Just to add on, there is a general rule for this where

${x}^{- n} = \frac{1}{x} ^ n$

And this is always true if I'm not mistaking

A more complex example would be

$3 {a}^{- 4} \cdot {b}^{2} \cdot 5 {c}^{- 7}$ which will be rewritten as

$\frac{15 {b}^{2}}{{a}^{4} \cdot {c}^{7}}$