# How do you simplify ((5pr^-2)^-2)/((3p^-1r)^3)?

Use the fact that ${\left({a}^{m}\right)}^{n} = {a}^{m \cdot n}$
$\frac{{5}^{- 2} {p}^{- 2} {r}^{\left(- 2\right) \cdot \left(- 2\right)}}{{3}^{3} {p}^{- 1 \cdot 3} {r}^{3}} =$
use the fact that ${a}^{-} m = \frac{1}{a} ^ m$
$\frac{1}{25} \cdot \frac{{p}^{- 2} {r}^{4}}{27 {p}^{- 3} {r}^{3}} =$
$= \frac{1}{675} \cdot r p$