How do you simplify #(5uv^6)/(u^2v^2)#?

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Answer 1 · 2015-11-01T01:41:17

#(5uv^6)/(u^2v^2)=(5v^4)/u#

#(5uv^6)/(u^2v^2)#

Apply exponent quotient rule: #a^m/a^n=a^(m-n)#.

#(5uv^6)/(u^2v^2)=#

#5u^(1-2)v^(6-2)#

Simplify.

#5u^(-1)v^4#

Apply the negative exponent rule: #a^(-m)=1/a^m#.

#5xx1/uxxv^4=#

#(5v^4)/u#