How do you simplify (5y^2)/(20x^2y^3)?

Apr 15, 2018

$\frac{1}{4 {x}^{2} y}$

Explanation:

$\frac{1}{4 {x}^{2} y}$

So think of the original question as.

$\frac{5}{20} . \frac{1}{x} ^ 2 . {y}^{2} / {y}^{3}$

$\frac{1}{4} . \frac{1}{x} ^ 2 . \frac{1}{y}$

$\frac{1}{4 {x}^{2} y}$