How do you simplify #6+12/3*2-(4+3)+2^3# using PEMDAS?

1 Answer
Mar 1, 2016

Answer:

Well, let's start with Paretheses:

Explanation:

P: #=6+12/3*2-7+2^3#
E: #=6+12/3*2-7+8#
MD: #=6+4*2-7+8=6+8-7+8#

AS: #=15#

Remember:
Multiplication and Division, and (in the following step) Adding and Subtracting go from left to right, in order.