# How do you simplify (6^-2x^3y^-4)/(2^-4x^3y^-4)?

May 25, 2018

$\frac{4}{9}$

#### Explanation:

The $x$ and $y$ terms have the same exponent on the top and bottom, so they will essentially cancel each other out. We're left with

${6}^{-} \frac{2}{2} ^ - 4$

We can rewrite this as being equal to

$\frac{\frac{1}{6} ^ 2}{\frac{1}{2} ^ 4}$

Which can be further simplified as follows

$\implies \frac{\frac{1}{36}}{\frac{1}{16}}$

$\implies \frac{1}{36} \cdot 16$

$\implies \frac{16}{36}$

$\implies \frac{4}{9}$

Hope this helps!