How do you simplify #(6-3x)/5 div(4x-8)/25#? Algebra Rational Equations and Functions Division of Rational Expressions 1 Answer Daniel L. Jul 13, 2015 #(6-3x)/5:(4x-8)/25=-3 3/4# Explanation: #(6-3x)/5:(4x-8)/25=(3(2-x))/5:(4(x-2))/25=# #=(3(2-x))/(cancel(5)^1)*(cancel(25)^5)/(4(x-2))=(15(2-x))/(4(x-2))=# #(-15cancel((x-2))^1)/(4cancel((x-2))^1)=-15/4=-3 3/4# Answer link Related questions What is Division of Rational Expressions? How does the division of rational expressions differ from the multiplication of rational expressions? How do you divide 3 rational expressions? How do you divide rational expressions? How do you divide and simplify #\frac{9x^2-4}{2x-2} -: \frac{21x^2-2x-8}{1} #? How do you divide and reduce the expression to the lowest terms #2xy \-: \frac{2x^2}{y}#? How do you divide #\frac{x^2-25}{x+3} \-: (x-5)#? How do you divide #\frac{a^2+2ab+b^2}{ab^2-a^2b} \-: (a+b)#? How do you simplify #(w^2+6w+5)/(w+5)#? How do you simplify #(x^4-256)/(x-4)#? See all questions in Division of Rational Expressions Impact of this question 1436 views around the world You can reuse this answer Creative Commons License