# How do you simplify 6+4 (3-1)^2 ÷ sqrt25 using PEMDAS?

Feb 26, 2016

PEMDAS

First, it is parenthesis, so we do $3 - 1 = 2$ first inside the parenthesis

Next is exponents, so we get ${2}^{2} = 4$

Now our equation looks like $6 + 4 \cdot \frac{4}{\sqrt{25}}$

We can get the square root out because $\sqrt{25} = 5$

So we have $6 + 4 \cdot \frac{4}{5}$

MD are together, so we multiply and divide

$6 + \frac{16}{5}$

$6 + 3.2$

$9.2$