How do you simplify #6+4times3# using order of operations?

1 Answer
Mar 9, 2018

#6+4xx3=color(red)18#

Explanation:

Using the #color(blue)("PEDMAS")# memory aid

Things in #color(blue)("P")#arentheses are evaluated first;
#color(white)("xxx")#then #color(blue)("E")#xponents;
#color(white)("xxx")#then #color(blue)("D")#ivision and #color(blue)("M")#ultiplication;
#color(white)("xxx")#then #color(blue)("A")#ddition and #color(blue)("S")#ubtraction
#color(white)("xxxxxx")#(with evaluation left-to-right for operations at the same level)

Therefore the Multiplication is done first
#color(white)("xxxxxx")6+underbrace(4xx3)#
#color(white)("xxx")=6+color(white)("X")12#
#color(white)("xxx")=18#