How do you simplify #(6+7^2) + 1# using order of operations?

1 Answer
Mark Kononov
Nov 19, 2015

The final number would be 56.

Explanation:

In the order of operations, it usually goes like PEMDAS. Parenthesis, Exponents, Multiplication/Division, Addition/Subtraction. We notice a set of parenthesis so that is what we solve for first. We then notice that inside the parenthesis are exponents so then we solve for that. #7^2# is 49, and then we add 6. We get 55 + 1, and we add those together to get 56.

Related questions
See all questions in PEMDAS
Impact of this question
1558 views around the world
You can reuse this answer
Creative Commons License