How do you simplify $(6 + 7^{2}) + 1$ $(6+7^2) + 1$ using order of operations?

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How do you simplify $(6 + 7^{2}) + 1$ $(6+7^2) + 1$ using order of operations?

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Answer 1 · 2015-11-19T21:41:20

The final number would be 56.

Explanation:

In the order of operations, it usually goes like PEMDAS. Parenthesis, Exponents, Multiplication/Division, Addition/Subtraction. We notice a set of parenthesis so that is what we solve for first. We then notice that inside the parenthesis are exponents so then we solve for that. $7^{2}$ $7^2$ is 49, and then we add 6. We get 55 + 1, and we add those together to get 56.

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How do you simplify $(6 + 7^{2}) + 1$ $(6+7^2) + 1$ using order of operations?

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How do you simplify $(6 + 7^{2}) + 1$ $(6+7^2) + 1$ using order of operations?