How do you simplify #(6/(x-2))/(3/(x^2-x-2))#?

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Answer 1 · 2017-02-14T14:49:24

#= 2(x+1), x ne 2#

#(6/(x-2))/(3/(x^2-x-2)) #

First turn it into a simpler fraction as follows:

#= (6(x^2 - x - 2))/(3(x-2)) = #

Factor numbers and the quadratic:

#= (2(x+1)(x-2))/((x-2))#

Careful with next step, we can cancel the #x -2#'s but we need to be clear that there is a singularity at #x = 2#:

#= 2(x+1), qquad x ne 2#