# How do you simplify (6/(x-2))/(3/(x^2-x-2))?

Feb 14, 2017

$= 2 \left(x + 1\right) , x \ne 2$

#### Explanation:

$\frac{\frac{6}{x - 2}}{\frac{3}{{x}^{2} - x - 2}}$

First turn it into a simpler fraction as follows:

$= \frac{6 \left({x}^{2} - x - 2\right)}{3 \left(x - 2\right)} =$

$= \frac{2 \left(x + 1\right) \left(x - 2\right)}{\left(x - 2\right)}$
Careful with next step, we can cancel the $x - 2$'s but we need to be clear that there is a singularity at $x = 2$:
$= 2 \left(x + 1\right) , q \quad x \ne 2$