How do you simplify #64^(-4/3)#?
1 Answer
Apr 28, 2017
Explanation:
Using the
#color(blue)"law of exponents"#
#color(red)(bar(ul(|color(white)(2/2)color(black)(a^(m/n)=(root(n)(a))^m" and "a^-mhArr1/a^m)color(white)(2/2)|)))#
#rArr64^(-4/3)#
#=1/(64^(4/3))#
#=1/(root(3)(64))^4#
#=1/(4)^4#
#=1/256#
