How do you simplify #64^(7)/(12)#? Algebra Exponents and Exponential Functions Exponential Properties Involving Quotients 1 Answer Alan N. Jun 8, 2017 #2^40/3# Explanation: #64 = 2^6# #12 = 2^2 xx 3# #:. 64^7/12 = (2^6)^7/(2^2xx3)# #= 2^42/(2^2xx3)# #= 1/3* 2^(42-2)# #= 2^40/3# Answer link Related questions What is the quotient of powers property? How do you simplify expressions using the quotient rule? What is the power of a quotient property? How do you evaluate the expression #(2^2/3^3)^3#? How do you simplify the expression #\frac{a^5b^4}{a^3b^2}#? How do you simplify #((a^3b^4)/(a^2b))^3# using the exponential properties? How do you simplify #\frac{(3ab)^2(4a^3b^4)^3}{(6a^2b)^4}#? Which exponential property do you use first to simplify #\frac{(2a^2bc^2)(6abc^3)}{4ab^2c}#? How do you simplify #(x^5y^8)/(x^4y^2)#? How do you simplify #[(2^3 *-3^2) / (2^4 * 3^-2)]^2#? See all questions in Exponential Properties Involving Quotients Impact of this question 3165 views around the world You can reuse this answer Creative Commons License