How do you simplify #(64x^5y^4z)^(2/3)#?

1 Answer
Ratnaker Mehta
Jun 17, 2016

#16*x^(10/3)*y^(8/3)*z^(2/3).#

Explanation:

Expression #=(64x^5y^4z)^(2/3)= (64^(2/3))(x^5)^(2/3)* (y^4)^(2/3)*z^(2/3),# .............[Rule : #(ab)^n=a^n*b^n]#
=#(4^3)^(2/3)*x^(5*2/3)*y^(4*2/3)*z^(2/3)#,........[Rule :#(a^m)^n=a^(mn)#]
#=4^(3*2/3)*x^(10/3)*y^(8/3)*z^(2/3)=4^2*x^(10/3)*y^(8/3)*z^(2/3)=16*x^(10/3)*y^(8/3)*z^(2/3).#

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