How do you simplify #(6y^2 + 18y)/( 2y^3 - 6y^2 - 36y )#?
1 Answer
Oct 7, 2015
Explanation:
#(6y^2 + 18y)/(2y^3 - 6y^2 - 36y)#
#(6cancel(y) (y+3))/(2cancel(y) * (y^2 - 3y - 18)) = (3(y+3))/(y^2 - 3y - 18)#
You can write the denominator as
#y^2 - 3y - 18 = y^2 - 6y + 3y - 18#
#y * (y + 3) - 6(y+3) = (y+3) * (y-6)#
The expression will thus be
#(3 * cancel(y+3))/(cancel(y+3) * (y-6)) = 3/(y-6)#
