How do you simplify #(6y^3 - 12y^2) /(12y^2 - 18)#?

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Answer 1 · 2015-07-05T11:01:21

Factor out the GCF in the numerator and denominator. Cancel the #6# in the numerator and denominator.

#(6y^3-12y^2)/(12y^2-18)#

Numerator

#6y3-12y^2#

Factor out #6y^2#

#6y^2(y-2)#

Denominator

#(12y^2-18)#

Factor out #6#.

#6(2y^2-3)#

Put them back together.

#((cancel6y^2)(y-2))/((cancel6)(2y^2-3))# =

#((y^2)(y-2))/(2y^2-3)#