How do you simplify #7/(5t)-(3+t)/(5t)#?
1 Answer
Mar 17, 2017
Explanation:
Before adding/subtracting fractions they must have a
#color(blue)"common denominator"# These fractions have a common denominator of
#color(blue)(5t)# and so we can subtract the numerators while leaving the denominator as it is.
#rArr7/(5t)-(3+t)/(5t)#
#=(7-(3+t))/(5t)#
#=(7-3-t)/(5t)#
#=(4-t)/(5t)#
