How do you simplify #7^-6/7^-8#?

Question

2234 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-11-28T05:46:01

#=7^2#

Recall the law of indices#" "x^-m = 1/x^m#

#7^-6/7^-8#

#=7^8 xx 7^-6#

#=7^(8-6) = 7^2#

Note you could also use the law#" " x^m/x^n = x^(m-n)#

#7^-6/7^-8#

#=7^(-6-(-8)) = 7^(-6+8)#

#=7^2#